JLPTN3 #N3vocabulary #n3word Chapter #1 အစအဆုံး (Section 1 to 5) ... <看更多>

This can be implemented using simple slicing. n = 3 word = "ABCDEFG" result = [word[i:i+n] for i in range(0, len(word), n)]. ... <看更多>

Overall Results -------------------------- SENT: %Correct=0.00 [H=0, S=3, N=3] WORD: %Corr=63.91, Acc=59.40 [H=85, D=35, S=13, I=6, ... ... <看更多>